Question 1

The density of silver is $$10.8 \times 10^3kgm^{-3}$$ and the density of water is $$10^3kgm^{-3}$$. What is the relative density of Ag?

Solution

The density of silver is $$10.8 \times 10^3kgm^{-3}$$ and the density of water is $$10^3kgm^{-3}$$.

In this case,

Relative density $$= \frac{Density of silver}{Density of water}$$

Relative density = $$\frac{10.8 \times 10^3kgm^{-3}}{10^3} kgm³$$

$$ = 10.8$$

Option D is correct.

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