Question 109

The sides of $$\triangle ABC$$ are 10 cm, 10.5 cm and 14.5 cm. Whatis the radius of its circumcircle?

Solution

The $$\triangle$$ ABC is a right angled triangle because

$$(14.5)^2=(10)^2+(10.5)^2=210.25$$

Also, circumradius of a right triangle is half of hypotenuse = $$\frac{14.5}{2}=7.25$$ cm

=> Ans - (D)

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