A man having height 169 cm is standing near a pole. He casts a shadow 130 cm long. What is the length of the pole if it gives a shadow 420 cm long ?
AB=h=Height of tower
DE=Height of man
CD=Shadow of man
BC=Shadow of tower
$$\because$$ $$\triangle$$CED is similar to $$\triangle$$ABC.
$$\therefore$$ $$\frac{DE}{AB}=\frac{CD}{BC}$$
$$\frac{169}{h}=\frac{130}{420}$$
$$h=546 cm$$
Therefore, Option D is correct.
Create a FREE account and get: