Jar A has 36 litres of mixture of milk and water in the respective ratio of 5 : 4. Jar B which had 20 litres of mixture of milk and water, was emptied into jar A, and as a result in jar A, the respective ratio of milk and water becomes 5: 3. What was the quantity of water in jar B?

Jar A has 36 litres of mixture of milk and water in the respective ratio of 5 : 4

=> Quantity of milk in Jar A = $$\frac{5}{9} \times 36 = 20$$ litres

Quantity of water in Jar A = $$36 - 20 = 16$$ itres

Let quantity of water in Jar B = $$x$$ litres

=> Quantity of milk in Jar B = $$(20 - x)$$ litres

Acc. to ques, => $$\frac{20 + (20 - x)}{16 + x} = \frac{5}{3}$$

=> $$120 - 3x = 80 + 5x$$

=> $$5x + 3x = 120 - 80$$

=> $$8x = 40$$

=> $$x = \frac{40}{8} = 5$$ litres