Question 16

The length of a rectangle is halved, and its breadth is tripled. What is the percentage change in its area?

Solution

let original length = x and original breadth = y.

Original area of rectangle = xy.

new length =$$\frac{x}{2}$$ and new breadth=3y

New area = $$\frac{3xy}{2}$$

so,Increase in area = New area-original area = $$\frac{3xy}{2}$$−xy= $$\frac{xy}{2}$$

sp, Increase %

= $$\frac{ increase in area}{ original area}100$$

= $$\frac{\frac{xy}{2}}{xy}\times 100$$

= 50%

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