RRB JE 25th May 2019 Shift-2

Question 2

If 8 # 2 @ 4 = 12 and 5 # 4 @ 2 = 18, then what will be 4 # 8 @ 3?

Solution

Here,

 # is ×(multiplication)

@ is -(substraction)

So,

8#2@4=12 will be 8×2-4=12

5#4@2=18 will be 5×4-2=18

Then 4#8@3 will be 4×8-3=29

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

  • Download RRB Study Material PDF
  • 45+ RRB previous papers with solutions PDF
  • 300+ Online RRB Tests for Free

cracku

Boost your Prep!

Download App