we know that ,
$$\left(x-y\right)^2=\left(x^2+y^2-2\times x\times y\right).$$
given that,Â
$$A=\left(-14+4\right)\&B=\left(4-14\right).$$
By rearranging above equation we get,
$$A=\left(4-14\right).$$
So,
$$AB=\left(4-14\right)\times\left(4-14\right).$$
or,$$AB=\left(4-14\right)^2.$$
or,$$AB=\left(4^2+14^2-2\times 4\times 14\right).$$
or,$$AB=\left(16+196-112\right).$$
or, $$AB=\left(212-112\right).$$
or,$$AB=100.$$
So, $$AB=100.$$
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