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Question 28
A body of mass 2 kg is thrown upward with initial velocity of 20 m/s. After 2 seconds,its kinetic energy will be: $$(g=10\frac{m}{s^2})$$
Solution
We know that, Kinetic energy isÂ
K.E. = $$\frac{1}{2}mv^2$$
$$V=u+at$$
$$u=20ms^{-1}$$
$$t=2\sec onds$$
$$a=-10ms^{-2}$$
Because, here body is going upward so we will take acceleration as negative.
$$v=20+2\left(-10\right)=20-20=0$$
K.E. = $$\frac{1}{2}mv^2$$
Hence K.E.= 0
Option A is right answer.
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