$$1035\div\left[\frac{3}{4}(71+65)−15\frac{3}{4}\right]$$
$$=1035\div\left[\frac{3}{4}(136)−\frac{63}{4}\right]$$
$$=1035\div\left[\frac{408-63}{4}\right]$$
$$=1035\times\ \frac{4}{345}$$
$$=3\times4=12.$$
A is correct choice.
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