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Question 39
What is the sum of the first 12 terms of an arithmetic progression if the first term is -19 and last term is 36?
Solution
First term of AP = $$a=-19$$ and last term = $$l=36$$
Number of terms = $$n=12$$
Sum of AP = $$\frac{n}{2}(a+l)$$
= $$\frac{12}{2}(-19+36)$$
= $$17 \times 6=102$$
=> Ans - (C)
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