A steel rod of length $$ 20 \frac{3}{26} $$ is cut out from a rod of length $$ 56 \frac{1}{5} $$. What then is the remaining length of the rod?

A

$$ 36 \frac{3}{130} $$

B

$$ 36 \frac{7}{130} $$

C

$$ 36 \frac{1}{130} $$

D

$$ 36 \frac{11}{130} $$