Question 5

From a cloth of 30 m long, 12 bits each measuring 225 cm are cut and sold. What fraction of the original length remains?

Solution

total length cut and sold=$$12\times225=2700\ cm\ =\ 27\ m.$$

So, cloth left=$$\left(30-27\right)\ m=3\ m.$$

So, required fraction=$$\frac{3}{30}=\frac{1}{10}.$$

D is correct choice.


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