Question 56

The ratio of the ages ofA and B, 8 years ago, was 2 : 3. Four years ago,the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?

Solution

8 years ago the ratio of the ages of A and B = 2 : 3

Let the 8 years ago ages of A and B be 2x and 3x respectively.

4 years age of A = 2x + 4

4 years agoof B = 3x + 4

Four years ago,the ratio of their ages = 5 : 7

 $$\frac{2x + 4}{3x + 4} = \frac{5}{7}$$

14x + 28 = 15x + 20

x = 8

8 years from now, Age of A = 2x + 16 = 2$$\times$$8 + 16 = 32

8 years from now, Age of B = 3x + 16 = 3$$\times$$8 + 16 = 40

Ratio of their ages 8 years from now = 32 : 40 = 4 : 5


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