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Question 58
The two roots of an quadratic equation are given as $$x = \frac{1}{2}$$ and $$x = \frac{-1}{3}$$. The equation can be written as:
Solution
The two roots of a quadratic equation are written as (x-h₁) and (x-h₂) where h is root. So our quadratic equation will be $$(x-\frac{1}{2})(x+\frac{1}{3})$$
$$(x-\frac{1}{2})(x+\frac{1}{3})=0$$
$$(\frac{2x-1}{2})(\frac{3x+1}{3})=0$$
$$({2x-1})({3x+1})=0$$
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