Question 63

Incentre of Δ ABC is I. ∠ABC = 90°and ∠ACB = 70°. ∠AIC is

Solution

Given : I is the incentre of $$\triangle$$ ABC and $$\angle$$ ABC = 90°

To find : $$\angle$$ AIC = $$\theta$$ = ?

Incentre of a triangle = $$90^\circ+\frac{1}{2} \times $$ (Angle opposite to it)

=> $$\theta=90^\circ+\frac{90^\circ}{2}$$

=> $$\theta=90^\circ+45^\circ$$

=> $$\theta=135^\circ$$

=> Ans - (A)

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