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Question 63
The value of $$\frac{7 - [4 + 3(2 - 2 \times 2 + 5) - 8] \div 5}{2 \div 2 of (4 + 4 \div 4 of 4)}$$ is:
Solution
$$\frac{7 - [4 + 3(2 - 2 \times 2 + 5) - 8] \div 5}{2 \div 2 of (4 + 4 \div 4 of 4)}$$
=Â $$\frac{7 - [4 + 3(2 - 4 + 5) - 8] \div 5}{2 \div 2 of (4 + 4 \div 16)}$$
= $$\frac{7 - [4 + 3(3) - 8] \div 5}{2 \div 2 of (4 + \frac{1}{4})}$$
= $$\frac{7 - 5 \div 5}{2 \div 2 of \frac{17}{4}}$$
= $$\frac{7 - 1}{2 \div \frac{17}{2}}$$
= $$\frac{6}{2 \times \frac{2}{17}}$$
= $$\frac{51}{2}$$ = $$25\frac{1}{2}$$
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