Question 66

In ∆ABC, ∠B is right angle, D is the mid point of the side AC. If AB = 6 cm, BC = 8cm, then the length of BD is

Solution

In $$\triangle$$ ABC, $$(AC)^2=(AB)^2+(BC)^2$$

=> $$(AC)^2=(6)^2+(8)^2$$

=> $$(AC)^2=36+64=100$$

=> $$AC=\sqrt{100}=10$$ cm

$$\because$$ D is the mid point of AC, thus AD = DC = 5 cm

Also, $$(BD)^2 = (AD) \times (DC)$$

=> $$(BD)^2 = 5 \times 5 = 25$$

=> $$BD=\sqrt{25}=5$$ cm

=> Ans - (B)

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