Question 67

A shopkeeper bought a machine for ₹4600 and spent ₹500 on its repairs and transport. He marked the machine at 8% above the over all cost price. If he sold the machine for ₹4681.80 after giving x% discount, then the value of x is:

Solution

Total cost price = 4600 + 500 = ₹5100

Marked price = $$\frac{108}{100}\times5100$$ = ₹5508

Discount = x%

Selling price = ₹4681.80

$$\frac{100-x}{100}\times5508=4681.80$$

100 - x = $$\frac{468180}{5508}$$

100 - x = 85

x = 15

Hence, the correct answer is Option A

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