If $$\sin(A + B) = 1$$ and $$\cos(A - B) = \frac{\sqrt{3}}{2}, A + B \leq 90^\circ$$ and $$A > B$$, then the value of $$\frac{5 \sin^2 B + 4 \tan^2 A}{2 \sin B \cos A}$$ is:

A

$$16\frac{1}{2}$$

B

18

C

20

D

$$26\frac{1}{2}$$