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If $$sin (A+B)= cos (A + B)$$, what is the value of tan A?
$$\frac{1-cosec \ B}{1+ cosec \ B}$$
$$\frac{1+tan \ B}{1-tan \ B}$$
$$\frac{1+sec \ B}{1-sec \ B}$$
$$\frac{1-tan \ B}{1+tan \ B}$$
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