A pyramid has an equilateral triangle as its base, of which each side is 8 cm. Its slant edge is 24 cm. The whole surface area of the pyramid (in $$cm^{2}$$) is:

A

$$(16\sqrt{3} + 24\sqrt{35}) $$

B

$$(12\sqrt{3} + 24\sqrt{35}) $$

C

$$(24\sqrt{3} + 36\sqrt{35}) $$

D

$$(16\sqrt{3} + 48\sqrt{35})$$