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Solution
Expression =Â $${(216)^{\frac{2}{3}}+(36)^-{\frac{1}{2}}}$$
=Â $${(6^3)^{\frac{2}{3}}+(6^2)^-{\frac{1}{2}}}$$
= $$6^2+6^{-1}$$
= $$36+\frac{1}{6}$$
= $$\frac{(216+1)}{6}=\frac{217}{6}$$
=> Ans - (D)
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