Question 1

$$\frac{9}{15}$$ of $$\frac{7}{3}$$ of a number is greater than $$\frac{7}{12}$$ of $$\frac{3}{5}$$ of the same number by 7. Find the number.

Solution

Let the number be $$x$$

According to ques,

=> $$(\frac{9}{15}\times\frac{7}{3}x)-(\frac{7}{12}\times\frac{3}{5}x)=7$$

=> $$(\frac{7x}{5})-(\frac{7x}{20})=7$$

=> $$\frac{x}{5}-\frac{x}{20}=1$$

=> $$\frac{4x-x}{20}=1$$

=> $$x=\frac{20}{3}=6.67$$

=> Ans - (B)

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