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Question 1
N solid metallic spherical balls are melted and recast into a cylindrical rod whose radius is 3 times that of a spherical ball and height is 4 times the radius of a spherical ball. The value of N is:
Solution
N $$\times$$ volume of solid metallic spherical balls = $$\times$$ volume of cylindrical rod
N $$\times \frac{4}{3} \pi r^3 = \pi (3r)^2(4r)$$
N $$\times \frac{4}{3} = 36$$
N = 27
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