Question 10

Average of 31 numbers is 19. If the average of first 8 numbers is 24, then what is the average of the remaining numbers?

Solution

Average of 31 numbers = 19

=> Sum of 31 numbers = $$19\times31=589$$

Average of first 8 numbers = 24

=> Sum of first 8 numbers = $$24\times8=192$$

Thus, sum of remaining (31-8) 23 numbers = $$589-192=397$$

$$\therefore$$ Required average = $$\frac{397}{23}=17.26$$

=> Ans - (A)

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