The sides AB and AC of $$\triangle$$ABC are produced to P and Q respectively. The bisectors af $$\angle$$CBP and $$\angle$$BCQ meet at R. If the measure of $$\angle$$A is $$44^\circ$$, then what is the measure of, $$\frac{1}{2} \angle$$BOC ?
$$\angle BRC = 90 \degree - \angle A/2$$
=Â $$90 \degree - 44\degree/2 =Â 90 \degree - 22\degree = 68\degree$$
$$\frac{1}{2} \angle BOC =Â \frac{68\degree}{2}$$
$$\frac{1}{2} \angle BOC = 34\degree$$
$$\therefore$$ The correct answer is option C.
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