Question 108

$$1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{2}{3}}}}}$$

Solution

In second term solving from the lowest part first denominator will be $$\frac{5}{3}$$
second denominator will be $$\frac{8}{5}$$
third denominator will be $$\frac{13}{8}$$
fourth denominator will be $$\frac{13}{21}$$
hence eq. will reduce to 1+$$\frac{13}{21}$$ = $$\frac{34}{21}$$

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