Question 11

What day of the week was 5 February 2008?

Solution

Odd days in year 2007 = 6 + 2 = 8
($$\because$$ 2004 is the leap year and odd days till 2000 is 0.)
Odd days in 5 February = odd days in January + 5 = 3 + 5 = 8
Total odd days = 8 + 8 = 16
Odd days = 16 = 2 weeks + 2 odd days
So day of the week was Tuesday.
$$\therefore$$ The correct answer is option C.


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