Question 110

The radius of a wire is decreased to one - third and its volume remains the same. The new length is how many times the original length?

Solution

We know that wire is in the shape of a cylinder.
So, the volume of wire = $$\pi\ r^2h$$

$$\pi\ r^2h_1$$ = $$\pi\ (\frac{r}{3})^2h_2$$

Cancelling π on both sides,

$$\ r^2h_1$$ = $$\frac{\ r}{9}^{^2}h_2$$
$$9h_1$$ = $$h_2$$
length is increased by 9 times

D is the correct answer.

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

All Quant Formulas and shortcuts PDF
170+ previous papers with solutions PDF
Top 5000+ MBA exam Solved Questions for Free

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Progressions and Series Questions SNAP Time, Distance and Work Questions SNAP Venn Diagrams Questions SNAP Probability, Combinatorics Questions SNAP Data Sufficiency Questions

SNAP DILR Questions | LRDI Questions For SNAP

SNAP Data Interpretation Questions SNAP Logical Reasoning Questions

SNAP Verbal Ability Questions | VARC Questions For SNAP

SNAP Para Summary Questions SNAP Para Jumbles Questions SNAP Vocabulary Questions SNAP Reading Comprehension Questions SNAP Grammar and Sentence Correction Questions

Also Read

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests

Follow us on

Boost your Prep!

Download App