Question 116

From a point P which is at a distance of 10 cm from the centre O of a circle of radius 6 cm, a pair of tangents PQ and PR to the circle at point Q and respectively, are drawn. Then the area of the quadrilateral PQOR is equal to

Solution

From the given question we draw the diagram

From the $$ \triangle $$

$$ x^2 = (10)^2 - (6)^2 $$

$$ x^2 = 100 - 36 $$

$$ x^2 = 64$$

$$ x = 8 $$

then area quadrilateral PQOR =$$ 2 \times \frac {1}{2} \times 6 \times 8 $$

= $$ 6\times 8 $$

= $$48 cm^2 $$ Ans

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