Two non-intersecting circles. one lying inside the other. are of radii r_1, and r_2, and r_1 > r_2. If the minimum distance between any two points on their circumferences is s, then the distance between their centres is:

Question 118

Two non-intersecting circles. one lying inside the other. are of radii $$r_1$$, and $$r_2$$, and $$r_1$$ > $$r_2$$. If the minimum distance between any two points on their circumferences is s, then the distance between their centres is:

Solution

Let 'a' be the radius of the bigger circle where A is its center, while 'b' is the radius of the smaller circle and B is its center.

's' is the distance between their circumference, and D is the distance between the two centers.

Hence, D = a - (b+s)

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