Solution
Given : O is the incentre of $$\triangle$$ PQR and $$\angle$$ POR = 115°
To find : $$\angle$$ PQR = $$\theta$$ = ?
Incentre of a triangle = $$90^\circ+\frac{\theta}{2}$$
=> $$115^\circ=90^\circ+\frac{\theta}{2}$$
=> $$\frac{\theta}{2}=115^\circ-90^\circ=25^\circ$$
=> $$\theta=25^\circ \times 2=50^\circ$$
=> Ans - (C)
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