To solve the equation, we shall first shift the 'x' in the base to RHS, which makes $$x^0$$ or 1.
Now, we will shift the '5' in the base to RHS, which becomes $$5^1$$ or 5 as the value in RHS. Meanwhile, the LHS becomes $$\sqrt{\ x+5}$$+$$\sqrt{\ x}$$.
Now, $$\sqrt{\ x+5}$$+$$\sqrt{\ x}$$ = 5.
The best way to proceed ahead is going through the options and substituting them in the equation. On doing so, we find out that x=4 would satisfy the equation and hence it is the correct answer.