The sum of all two digit numbers that give a remainder 2 when they are divided by 7 is _______
$$\frac{12}{2}\left(16+93\right)$$The numbers will be of the form 7k+2 where k is an whole number.
The smallest two digit number is when k=2 which is 16 and the largest 2 digit number is 93 k= 13
So sum = 16+23+.... +93Â which are in AP.Â
Sum to n terms of an AP= n/2(a+l), where n=number of terms , a=1st term ,l=last term
Here n=12 , a=16 , l=93
Hence sum =Â 654
Create a FREE account and get: