If $$a_1 = 1$$ and $$a_{n+1} = 2a_n +5$$, n=1,2,....,then $$a_{100}$$ is equal to:

A

$$(5*2^{99}-6)$$

B

$$(5*2^{99}+6)$$

C

$$(6*2^{99}+5)$$

D

$$(6*2^{99}-5)$$