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If $$4 - 2 \sin^2 \theta - 5 \cos \theta = 0, 0^\circ < \theta < 90^\circ$$, then the value of $$\cos \theta - \tan \theta$$ is:
$$\frac{1 + 2 \sqrt 3}{2}$$
$$\frac{2 - \sqrt 3}{2}$$
$$\frac{2 + \sqrt 3}{2}$$
$$\frac{1 - 2 \sqrt 3}{2}$$
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