Solution
Given : $$\frac{a}{b}=\frac{c}{d}=5$$
Let $$a=c=5$$ and $$b=d=1$$
To find : $$\frac{3a+4c}{3b+4d}$$
= $$\frac{3(5)+4(5)}{3(1)+4(1)}$$
= $$\frac{15+20}{3+4}$$
= $$\frac{35}{7}=5$$
=> Ans - (C)
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