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Solution
Expression : $$\frac{(3-2\sqrt2)}{(3+2\sqrt2)}$$
Rationalizing the denominator,
= $$\frac{(3-2\sqrt2)}{(3+2\sqrt2)}\times\frac{(3-2\sqrt2)}{(3-2\sqrt2)}$$
= $$\frac{(3-2\sqrt2)^2}{(3+2\sqrt2)(3-2\sqrt2)}$$
= $$\frac{(3-2\sqrt2)^2}{9-8}=(3-2\sqrt2)^2$$
Thus, square root is = $$3-2\sqrt2$$
=> Ans - (A)
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