Solution
$$\frac{75\times75-26\times26}{101}$$ = $$ \frac{75^{2}-26^{2}}{101}$$
==>$$ \frac{(75+26)(75-26)}{101}$$ ( $$\because a^{2}-b^{2}=(a+b)(a-b)$$)
= $$\frac{101\times49}{101} = 49$$
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