Question 16

A can do a piece of work in 25 days and B in 20 days. They work together for 5 days and then A goes away. In how many days will B finish the remaining work ?

Solution

Let 100 units of work be there.

$$\eta_A=\ \ \frac{\ 100}{25}=4units\ per\ day$$

$$\eta_B=\ \ \frac{\ 100}{20}=5units\ per\ day$$

Amount of work done when they work together for 5 days = $$5\times\ \left(\eta_A+\eta_B\right)\ =\ 5\times\ \left(5+4\right)\ =\ 45\ units$$

Remaining work = 100-45 = 55 units

Time taken by B = $$\ \frac{\ 55}{5}=11\ days$$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Data Interpretation Questions SNAP Logical Reasoning Questions

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests