Question 2

Calculate the value of $$\frac{\sqrt{5}}{(5-\sqrt5)}$$, if $$\sqrt5=2.236$$

Solution

Given : $$\sqrt5=2.236$$

To find : $$\frac{\sqrt{5}}{(5-\sqrt5)}$$

= $$\frac{\sqrt{5}}{\sqrt5(\sqrt5-1)}=\frac{1}{\sqrt5-1}$$

Rationalizing the denominator, we get :

= $$\frac{1}{(\sqrt5-1)}\times\frac{(\sqrt5+1)}{(\sqrt5+1)}$$

= $$\frac{\sqrt5+1}{5-1}=\frac{\sqrt5+1}{4}$$

= $$\frac{2.236+1}{4}=\frac{3.236}{4}=0.809$$

=> Ans - (A)

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