Question 20

A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ........

Solution

Here, work done by the body will be kinetic energy provided by given force.

We have

$$M=4.0kg$$

$$V=5ms^{-1}$$

K.E. = $$\frac{1}{2}mv^2$$

=$$\frac{1}{2}\times4.0\times5^{2}$$

= 50 J

Hence Option (A) is right answer.

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