Let the function $$f$$ be defined on the set of real numbers by
$$ f(x) = \begin{cases}x^2 - x, & if x < 1\\\frac{x^2 - 1}{3}, &if x \geq 1\end{cases}$$ then which of the following statement is TRUE ?
$$f'\left(x\right)=2x-1\ \ ,\ x<1$$
$$f'\left(x\right)=\frac{2x}{3}\ \ ,\ x\ge\ 1$$
$$f'\left(1^+\right)=\frac{2}{3}\ \ \ and\ f'\left(1^-\right)=1$$ => Right hand Derivative is not equal to LHD. Hence is is not differentiable at x=1
Left hand limit = 0 and RHL = 0. Hence it is continuos at x=1
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