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The probability that a randomly chosen positive divisor of $$10^{2023}$$ is an integer multiple of $$10^{2001}$$ is
$$\frac{22}{2023}$$
$$\frac{23}{2024}$$
$$\frac{22^{2}}{2023^{2}}$$
$$\frac{23^{2}}{2024^{2}}$$
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