Which two signs should be interchanged in the following equation to make it correct?
$$9-3+12\times8\div4=11$$
By Trial and Error method,
Option A
$$9+3-12\times8\div4=11$$
$$9+3-12\times2=11$$
$$9+3-24=11$$
$$-12=11$$
Hence option A is incorrect
Option B
$$9-3\times12+8\div4=11$$
$$9-3\times12+2=11$$
$$9-36+2=11$$
$$-25=11$$
Hence option B is incorrect
Option C
$$9\div3+12\times8-4=11$$
$$3+12\times8-4=11$$
$$3+96-4=11$$
$$95=11$$
Option D
$$9-3\div12\times8+4=11$$
$$9-\frac{1}{4}\times8+4=11$$
$$9-2+4=11$$
$$11=11$$
Hence, the correct answer is Option A
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