The given system of equations is $$2x + 4y + 16 = 0 \Rightarrow 1$$ and $$3x + 6y + 24 = 0 \Rightarrow 2$$
Let's multiply equation 1 by three and equation 2 by 2.
We get $$6x + 12y + 48 = 0 \Rightarrow 1$$ $$6x + 12y + 48 = 0 \Rightarrow 2$$
Both the lines are collinear, and the number of solutions is infinite.
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