Question 27

The perimeters of a square and a rectangle are equal . If their area be 'A' m2 and 'B' m2 then correct statement is

Solution

Let side of square = $$s$$ and length and breadth of rectangle be $$l$$ and $$b$$ respectively.

According to ques, Perimeter of square = Perimeter of rectangle

=> $$4s=2(l+b)$$

=> $$2s=l+b$$

Thus, $$l,s,b$$ are in A.P. and $$s^2$$ > $$lb$$

For example : $$4,6,8$$ where $$6^2$$ > $$4\times8$$

Thus, A > B

=> Ans - (C)

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