In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is
Let total population of city = 100
Total number of illiterates = $$\frac{40}{100} \times 100=40$$
Number of poor people = $$\frac{60}{100} \times 100=60$$
=> Number of rich people = $$100-60=40$$
Now, number of rich who are illiterate = $$\frac{10}{100} \times 40=4$$
=> Remaining illiterates are poor = $$40-4=36$$
$$\therefore$$ Percentage of the illiterate poor population = $$\frac{36}{60} \times 100$$
= $$36 \times \frac{5}{3}=60\%$$
=> Ans - (B)
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