A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A

$$\frac {4 \pi}{\sqrt 5}$$

B

$$\frac {2 \pi}{\sqrt 3}$$

C

$$\frac {\sqrt 5}{\pi}$$

D

$$\frac {\sqrt 5}{2 \pi}$$