$$\cot^4\theta+\cot^2\theta=3$$
$$\cot^2\theta(Cot^2\theta+1) = 3$$.......(i)
ButÂ
$$1+ \cot^2\theta = \cosec^2\theta$$......(ii)
=> $$\cot^2\theta = \cosec^2\theta - 1$$......(iii)
From (i), (ii) and(iii)
$$(\cosec^2\theta - 1)(\cosec^2\theta) = 3$$
$$cosec^4\theta-cosec^2\theta=3$$
Hence Option (B) is right answer.
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